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Electronics 9 min read

How Much Current Can a 10 mil Trace Carry? PCB Widths From 4 to 50 mil

Observation recorded
A 10 mil copper trace drawn to scale on a green board against a millimetre ruler: 0.89 A on 1 oz outer copper at a 10 °C rise

Ten mil, 0.254 mm, is the trace width many PCB tools start you on. It is narrow enough to route between pins and wide enough for most board houses to etch reliably. Sooner or later it ends up carrying more than a logic signal: an LED, a sensor's supply, a small relay coil. So how much current is too much?

By IPC-2221, the standard most trace calculators use, a 10 mil trace on 1 oz outer copper carries about 0.89 A with a 10 °C temperature rise. The PCB trace width calculator gives the current for any width, or the width for any current, and draws the trace to scale against a ruler; every number here comes from it.

Quick answerOn 1 oz outer copper, a 10 mil (0.254 mm) trace carries about 0.89 A for a 10 °C rise, 1.20 A for 20 °C and 1.44 A for 30 °C. On an inner layer IPC-2221 allows half, 0.44 A at 10 °C. On 2 oz copper the same width carries 1.46 A at 10 °C.

Where the number comes from

IPC-2221 gives charts of current against copper cross-section for several temperature rises. Calculators use a curve fit to those charts; the version Advanced Circuits publishes with its calculator is:

I=k⋅ΔT0.44⋅A0.725I = k \cdot \Delta T^{0.44} \cdot A^{0.725}

Here A is the copper cross-section in square mil, ΔT the temperature rise in °C, and k = 0.048 for outer layers in air or 0.024 for inner layers. Copper weight sets the thickness: one ounce per square foot is 1.378 mil, about 35 µm.

Example 1: a 10 mil trace on 1 oz outer copper, 10 °C rise

A=10×1.378=13.78 mil2I=0.048×100.44×13.780.725=0.048×2.754×6.70=0.89 A\begin{aligned}A &= 10 \times 1.378 = 13.78\ \text{mil}^2 \\ I &= 0.048 \times 10^{0.44} \times 13.78^{0.725} \\ &= 0.048 \times 2.754 \times 6.70 = 0.89\ \text{A}\end{aligned}

Allow 20 °C instead and 100.44 becomes 200.44 = 3.737, giving 1.20 A.

A 10 mil (0.254 mm) copper trace drawn to scale on a green board against a millimetre ruler: 0.89 A on 1 oz outer copper at a 10 °C rise, with a cross-section inset showing 35 µm of copper
Figure 1. A 10 mil trace, magnified, with the ruler in millimetres. The inset shows the copper to scale: 35 µm thick, 254 µm wide. Open this in the calculator.

Where those constants come from, why the internal chart is suspect, and how the newer IPC-2152 data compares, are covered in PCB trace width for current: IPC-2221 vs IPC-2152. This post stays with the practical question: what does each common width carry?

Current for common trace widths

WidthmmOuter, 10 °COuter, 20 °COuter, 30 °CInner, 10 °COuter 2 oz, 10 °C
4 mil0.1020.46 A0.62 A0.74 A0.23 A0.75 A
6 mil0.1520.61 A0.83 A0.99 A0.31 A1.01 A
8 mil0.2030.75 A1.02 A1.22 A0.38 A1.25 A
10 mil0.2540.89 A1.20 A1.44 A0.44 A1.46 A
12 mil0.3051.01 A1.37 A1.64 A0.51 A1.67 A
15 mil0.3811.19 A1.61 A1.93 A0.59 A1.96 A
20 mil0.5081.46 A1.99 A2.37 A0.73 A2.42 A
30 mil0.7621.96 A2.66 A3.18 A0.98 A3.25 A
50 mil1.2702.84 A3.86 A4.61 A1.42 A4.70 A

The charts behind the fit cover 10 to 100 °C of rise, 0.5 to 3 oz copper, up to 35 A and up to 400 mil, so everything in this table sits inside them.

A 6 mil (0.152 mm) trace against the ruler: 0.61 A on 1 oz outer copper at a 10 °C rise
Figure 2. A 6 mil trace, typical for fine-pitch signals, still carries about 0.61 A on the surface. Open this in the calculator.

Doubling the width does not double the current

Look down the table: 10 mil carries 0.89 A, 20 mil carries 1.46 A. Twice the copper gives 65% more current, not 100%. The exponent 0.725 is the reason. A wider trace has more cross-section to carry current, but its surface area for shedding heat grows more slowly in comparison, so each extra mil is worth a little less.

I20I10=20.725=1.65\frac{I_{20}}{I_{10}} = 2^{0.725} = 1.65

Turned around, a trace for twice the current must be 21/0.725 = 2.6 times as wide. The same factor appears between inner and outer layers, because IPC-2221 allows inner traces half the current.

1 A on 1 oz outer copper needs an 11.8 mil (0.30 mm) trace, with a dashed outline showing the 30.8 mil an inner layer would need
Figure 3. For 1 A at a 10 °C rise: 11.8 mil on the surface, 30.8 mil (dashed) on an inner layer by IPC-2221. Open this in the calculator.

Which temperature rise should you use?

A 10 °C rise is the usual conservative choice, and the one most tables quote. 20 °C is common for power traces on boards that are not in a hot enclosure. Above that, remember that the rise adds to the ambient: a board inside a 50 °C box with a 30 °C rise puts the copper at 80 °C, and FR-4 and nearby parts have to live with it.

Going from a 10 °C to a 20 °C allowance raises the current by 20.44 = 1.36 times. That is a cheaper way to carry 1.2 A on 10 mil than widening the trace, but only if the heat has somewhere to go.

Inner layers and thicker copper

IPC-2221 halves the current for buried traces. Michael Jouppi, writing about the new IPC-2152 standard, noted that the internal chart was not based on testing internal conductors, and that testing showed internal and external traces have close to the same temperature rise. The calculator still shows the IPC-2221 inner figure because it is what most checks expect, but treat it as a safe floor rather than a measurement.

2 A on an inner layer needs 80 mil (2.03 mm) by IPC-2221, with the 30.8 mil outer-layer width dashed inside it and the trace buried in the cross-section
Figure 4. 2 A on an inner layer: 80 mil by IPC-2221, against 30.8 mil on the surface. Open this in the calculator.

Copper weight works through area. A 10 mil trace in 2 oz copper has the same cross-section as a 20 mil trace in 1 oz, so it carries the same 1.46 A. Outer layers are also plated during manufacture: NCAB describes the IPC finished-copper table as foil plus an average of 20 µm of plating, so a "1 oz" outer trace usually ends up thicker than 35 µm, adding margin.

How much voltage does a 10 mil trace drop?

Heat is one limit; voltage drop is the other, and on thin traces it often matters first. Copper's resistivity is 1/58 Ω·mm²/m at 20 °C and rises 0.393% per °C, by the NBS copper wire tables.

Example 2: 100 mm of 10 mil, 1 oz trace at 0.5 A

A=13.78 mil2=0.00889 mm2ρ35 °C=158(1+0.00393×15)=0.01826 Ω mm2/mR=0.01826×0.10.00889=0.205 ΩV=0.5×0.205=0.10 V\begin{aligned}A &= 13.78\ \text{mil}^2 = 0.00889\ \text{mm}^2 \\ \rho_{35\,°\text{C}} &= \tfrac{1}{58}(1 + 0.00393 \times 15) \\ &= 0.01826\ \Omega\,\text{mm}^2/\text{m} \\ R &= \frac{0.01826 \times 0.1}{0.00889} = 0.205\ \Omega \\ V &= 0.5 \times 0.205 = 0.10\ \text{V}\end{aligned}

A tenth of a volt is 3% of a 3.3 V rail, from a trace that is nowhere near its thermal limit. For supply lines, check the drop as well as the width.

When 10 mil is not enough

Above about an amp, widths grow quickly. 5 A on 2 oz outer copper needs about 109 mil; 10 A on 2 oz copper with a 20 °C allowance needs 93 mil, 2.36 mm. At that point, copper pours, planes or several layers in parallel are usually easier than one wide trace.

10 A on 2 oz outer copper at a 20 °C rise needs 93 mil (2.36 mm), drawn to scale with a stronger heat tint; an inner layer would need 242 mil
Figure 5. 10 A on 2 oz copper at a 20 °C rise: 93 mil on the surface, 242 mil inside. Open this in the calculator.
PCB trace width calculator for a 10 mil trace on 1 oz outer copper: 0.89 A at a 10 °C rise, 0.44 A on an inner layer, 103 milliohms and 91 mV drop over 50 mm, with the IPC-2221 working
Figure 6. The full calculator for a 10 mil trace, with resistance, drop and the IPC-2221 working. Open this in the calculator.

To check your own traces, open the PCB trace width calculator, switch between finding a current and finding a width, and set the copper weight, layer and temperature rise your board needs.

Sources

Frequently asked questions

How much current can a 10 mil trace carry?

About 0.89 A on 1 oz outer copper for a 10 °C temperature rise, 1.2 A for a 20 °C rise and 1.44 A for 30 °C, by the IPC-2221 curve fit. On an inner layer IPC-2221 allows half: 0.44 A at 10 °C.

How much current can a 6 mil trace carry?

About 0.61 A on 1 oz outer copper for a 10 °C rise and 0.83 A for 20 °C, by IPC-2221. On an inner layer, about 0.31 A at 10 °C.

Does doubling the trace width double the current?

No. In IPC-2221 current grows with the copper area to the power 0.725, so doubling the width raises the current by about 65%: a 20 mil trace carries 1.46 A against 0.89 A for 10 mil at a 10 °C rise.

How wide is 10 mil in mm?

0.254 mm. One mil is a thousandth of an inch, 0.0254 mm.

Is 1 A too much for a 10 mil trace?

On 1 oz outer copper it means a rise of about 13 °C by IPC-2221, which most boards tolerate. On an inner layer or in a hot enclosure, go wider; 12 mil keeps 1 A to a 10 °C rise on the surface.

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